Implication Details

Assumptions: disjoint finite coproducts, strict terminal object

Conclusions: thin

Reason: Let $1$ be the strict terminal object, and let $A$ be any object. Then $1 \to A + 1$ is an isomorphism, since $1$ is strict. Also, $A \to A + 1$ is a monomorphism by assumption. It follows that the unique morphism $u : A \to 1$ is a monomorphism. For all $f,g : B \to A$ we have $uf = ug$ (since $1$ is terminal), hence $f = g$ .