Exact filtered colimits descend to nice subcategories
Lemma. Let G:C→D be a fully faithful functor with a left adjoint F:D→C that preserves finite limits. Assume that D has exact filtered colimits and that C has finite limits. Then C has exact filtered colimits as well.
Proof.
It is well-known (and easy to prove) that the colimit of a diagram (Xj) in C is constructed as F(colimjG(Xj)), provided that colimit in D exists. In particular, C has filtered colimits. By assumption, it also has finite limits, and G preserves these since it is a right adjoint. Now let X:I×J→C be a diagram, where I is finite and J is filtered. We compute:
colimjlimiX(i,j)≅F(colimjG(limiX(i,j)))≅F(colimjlimiG(X(i,j)))≅F(limicolimjG(X(i,j)))≅limiF(colimjG(X(i,j)))≅limicolimjX(i,j)
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