Implication Details

Claim: If a category is left cancellative and has zero morphisms, then it is thin.

Proof: If f,g:A⇉Bf,g : A \rightrightarrows B are two morphisms, then 0B,B∘f=0A,B=0B,B∘g0_{B,B} \circ f = 0_{A,B} = 0_{B,B} \circ g, so that f=gf = g.

This implication has a dual.

Show 32 categories using this implication