Implication Details
Claim: If a functor is full on isomorphisms, then it is essentially injective.
Proof: This is trivial.
Show 34 functors using this implication
- abelianization functor for groups
- binary coproduct functor on sets
- binary product functor on sets
- Brauer group functor
- functor of continuous functions
- countable copower functor on sets
- empty functor to the category of sets
- enveloping group functor
- forgetful functor from rings to monoids
- forgetful functor from finite sets to sets
- forgetful functor from finite abelian groups to abelian groups
- forgetful functor from finite groups to groups
- forgetful functor for groups
- forgetful functor from groups to pointed sets
- forgetful functor for rings
- forgetful functor for topological spaces
- forgetful functor for vector spaces
- group of units functor
- inclusion functor from extended natural numbers to ordinal numbers
- modulo p functor
- monoid ring functor
- morphism endpoints inclusion
- p-torsion functor
- path components functor
- fundamental group functor
- rational product functor
- ring idempotents functor
- sequences functor on sets
- simple-group probing functor
- span endpoints inclusion
- Stone-Čech compactification functor
- torsion functor
- trivial functor from the category of groups
- trivial functor from the category of sets