Implication Details
Assumptions: left-invertible
Conclusions: conservative, essentially injective, faithful
Proof: Let be a left-inverse to , meaning that . Then implies for all . Thus, essentially injective. Moreover, since is faithful, the composed map is injective, so that also is injective. This shows that is faithful. Finally, if is am morphism such that is an isomorphism, then is an isomorphism. Since in , we conclude that is an isomorphism. Therefore, is conservative.
Show 22 functors using this implication
- abelianization functor for groups
- functor of continuous functions
- binary coproduct functor on sets
- countable copower functor on sets
- binary diagonal functor on the category of sets
- discrete topology functor
- enveloping group functor
- forgetful functor from abelian groups to groups
- forgetful functor from rings to monoids
- forgetful functor for groups
- forgetful functor from groups to monoids
- forgetful functor for rings
- forgetful functor for topological spaces
- forgetful functor for vector spaces
- group of units functor
- identity functor on the category of sets
- modulo p functor
- monoid ring functor
- p-torsion functor
- binary product functor on sets
- sequences functor on sets
- torsion functor