Structure

Implication details

Claim: If a morphism is a regular monomorphism, then it is a strict monomorphism.

Proof: Let m:A→Bm : A \to B be the equalizer of f,g:B⇉Cf,g : B \rightrightarrows C. In particular, mm is a monomorphism. Let t:T→Bt : T \to B be a morphism that equalizes all pairs that are equalized by mm. In particular, tt equalizes f,gf,g, i.e. f∘t=g∘tf \circ t = g \circ t. By definition of an equalizer, this means that tt factors through mm.

This implication has a dual.

Show 14 morphisms using this implication