Baer-Specker relations
Consider the Baer-Specker group and choose a free abelian group with an epimorphism (for example, to make this example explicit, the free abelian group on the underlying set of ). Let be its kernel (which is also free abelian). In this entry, we consider the inclusion . It provides an example of a strict monomorphism which is not regular.
Satisfied properties
Assigned properties
- is a strict monomorphism
Deduced properties
- is a strong monomorphism
- is an extremal monomorphism
- is a monomorphism
Unsatisfied properties
Assigned properties
- is not a regular monomorphism
- is not a zero morphism
Deduced properties*
- is not constant
- is not a split monomorphism
- is not an effective monomorphism
- is not a normal monomorphism
- is not coconstant
- is not an isomorphism
- is not an epimorphism
- is not a split epimorphism
- is not an extremal epimorphism
- is not a strong epimorphism
- is not a strict epimorphism
- is not a regular epimorphism
- is not an effective epimorphism
- is not a normal epimorphism
*This also uses the deduced satisfied properties.
Unknown properties
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