Proof: Let f:A→B be a constant morphism in a category with zero morphisms. Then it is the zero morphism 0A,B because f=f∘idA=f∘0A,A=0A,B. Furthermore, 0A,B is coconstant because for all g,h:B⇉C we have g∘0A,B=0A,C=h∘0A,B. (A similar argument shows that 0A,B is also constant.)